By: KDKA-TV News Staff

PITTSBURGH (KDKA) – Make it four times for Steelers’ linebacker has been named the AFC Defensive Player of the Week.

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It was announced Wednesday morning that Watt was named the week six AFC Defensive Player of the Week.

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During Sunday’s night victory over Seattle, Watt recorded seven tackles, two sacks, three pass defenses, and a forced fumble in overtime that ultimately led to the game-winning field goal from Chris Boswell.

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Watt was most recently named AFC Defensive Player of the Week in week two of the 2020 season.